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Continuity - Notes, Concept and All Important Formula

CONTINUITY

1. CONTINUOUS FUNCTIONS:

A function f(x) is said to be continuous at x=a, if limxaf(x) exists and is equal to f( a). Symbolically f(x) is continuous at x=a.
If limh0f(ah)=limh0f(a+h)=f(a)= finite and fixed quantity (h>0).
i.e. LHL|x=a=RHL|x=a= value of f(x)|x=a= finite and fixed quantity.
At isolated points functions are considered to be continuous.



2. CONTINUITY OF THE FUNCTION IN AN INTERVAL:

(a) A function is said to be continuous in (a,b) if f is continuous at each & every point belonging to (a,b).

(b) A function is said to be continuous in a closed interval [a,b] if :

 f is continuous in the open interval (a,b).

 f is right continuous at 'a' i.e. limxa+f(x)=f(a)=a finite quantity.

 f is left continuous at 'b' i.e. limxhf(x)=f(b)=a finite quantity.

Note :

(i) All Polynomials, Trigonometrical functions, exponential & Logarithmic functions are continuous in their domains.

(ii) If f &  g are two functions that are continuous at x=c then the function defined by : F1(x)=f(x)±g(x);F2(x)=Kf(x),K any real number, F3(x)=f(x)g(x) are also continuous at x=c. Further, if g(c) is not zero, then F4(x)=f(x)g(x) is also continuous at x=c.

(iii) If f and g are continuous then fog and gof are also continuous.

(iv) If f and g are discontinuous at x=c, then f+g,fg,f.g may still be continuous.

(v) Sum or difference of a continuous and a discontinuous function is always discontinuous.




3. REASONS OF DISCONTINUITY:

REASONS OF DISCONTINUITY

(a) Limit does not exist i.e. limxaf(x)limxa+f(x)

(b) limxaf(x)f(a) Geometrically, the graph of the function will exhibit a break at x=a, if the function is discontinuous at x=a. The graph as shown is discontinuous at x=1,2 and 3 .




4. THE INTERMEDIATE VALUE THEOREM :

Suppose f(x) is continuous on an interval I and a and b are any two points of I. Then if y0 is a number between f(a) and f(b), their exists a number c between a and b such that f(c)=y0.

THE INTERMEDIATE VALUE THEOREM

Note that a function f which is continuous in [a,b] possesses the following property.

If f(a) & f(b) posses opposite signs, then there exists atleast one solution of the equation f(x)=0 in the open interval (a,b).



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