3D-COORDINATE GEOMETRY
1. DISTANCE FORMULA:
The distance between two points A(x1,y1,z1) and B(x2,y2,z2) is given by AB=√[(x2−x1)2+(y2−y1)2+(z2−z1)2]
2. SECTION FORMULAE :
Let P(x1,y1,z1) and Q(x2,y2,z2) be two points and let R(x,y,z) dividePQ in the ratio m1:m2. Then R is
(x,y,z)=(m1x2+m2x1m1+m2,m1y2+m2y1m1+m2,m1z2+m2z1m1+m2)
If (m1/m2) is positive, R divides PQ internally and if (m1/m2) is negative, then externally.
Mid point of PQ is given by (x1+x22,y1+y22,z1+z22)
3. CENTROID OF A TRIANGLE :
Let A(x1,y1,z1),B(x2,y2,z2),C(x3,y3,z3) be the vertices of a triangle ABC. Then its centroid G is given by
G=(x1+x2+x33,y1+y2+y33,z1+z2+z33)
4. DIRECTION COSINES OF LINE :
If α,β,γ be the angles made by a line with x -axis, y -axis & z -axis respectively then cosα,cosβ & cosγ are called direction cosines of a line, denoted by 1,m & n respectively and the relation between ℓ,m,n is given by ℓ2+m2+n2=1
Direction cosine of x -axis, y -axis &z -axis are respectively (1,0,0;0,1,0;0,0,1)
5. DIRECTION RATIOS :
Any three numbers a, b, c proportional to direction cosines ℓ,m,n are called direction ratios of the line.
i.e. ℓa=mb=nc
It is easy to see that there can be infinitely many sets of direction ratios for a given line.
6. RELATION BETWEEN D.C'S & D.R'S:
ℓa=mb=nc
∴ℓ2a2=m2b2=n2c2=ℓ2+m2+n2a2+b2+c2
∴ℓ=±a√a2+b2+c2;m=±b√a2+b2+c2;n=±c√a2+b2+c2
7. DIRECTION COSINE OF AXES :
Direction ratios and Direction cosines of the line joining two points:
Let A(x1,y1,z1) and B(x2,y2,z2) be two points, then d.r.'s of AB are x2−x1,y2−y1,z2−z1 and the d.c.'s of AB are 1r(x2−x1),1r(y2−y1) 1r(z2−z1) where r=√[Σ(x2−x1)2]=|→AB|
8. PROJECTION OF A LINE ON ANOTHER LINE :
Let PQ be a line segment with P(x1,y1,z1) and Q(x2,y2,z2) and let L be a straight line whose d.c.'s are ℓ,m,n. Then the length of projection of PQ on the lineL is |ℓ(x2−x1)+m(y2−y1)+n(z2−z1)|
9. ANGLE BETWEEN TWO LINES :
Let θ be the angle between the lines with d.c.'s l1,m1,n1 and l2,m2, n2 then cosθ=l1l2+m1m2+n1n2. If a1,b1,c1 and a2,b2,c2 be D.R.'s of two lines then angle θ between them is given by
cosθ=(a1a2+b1b2+c1c2)√(a21+b21+c21)√(a22+b22+c22)
10. PERPENDICULARITY AND PARALLELISM:
Let the two lines have their d.c.'s given by l1,m1,n1 and l2,m2,n2 respectively then they are perpendicular if θ=90∘ i.e. cosθ=0, i.e. l1l2+m1m2+n1n2=0
Also the two lines are parallel if θ=0 i.e. sinθ=0, i.e. ℓ1ℓ2=m1m2=n1n2
Note:
If instead of d.c.'s, d.r.'s a1,b1,c1 and a2,b2,c2 are given, then the lines are perpendicular if a1a2+b1b2+c1c2=0 and parallel if a1/a2=b1/b2=c1/c2
11. EQUATION OF A STRAIGHT LINE IN SYMMETRICAL FORM :
(a) One point form : Let A(x1,y1,z1) be a given point on the straight line and l,m,n the d.c's of the line, then its equation is
x−x1ℓ=y−y1m=z−z1n=r (say)
It should be noted that P(x1+lr,y1+mr,z1+nr) is a general point on this line at a distance r from the point A(x1,y1,z1) i.e. AP=r. One should note that for AP=r;1,m,n must be d.c.'s not d.r.'s. If a,b,c are direction ratios of the line, then equation of the line is x−x1a=y−y1b=z−z1c=r but here AP≠r.
(b) Equation of the line through two points A(x1,y1,z1) and B(x2,y2,z2) is x−x1x2−x1=y−y1y2−y1=z−z1z2−z1
12. FOOT, LENGTH AND EQUATION OF PERPENDICULAR FROM A POINT TO A LINE:
Let equation of the line be
x−x1ℓ=y−y1m=z−z1n=r. (say) ......(i)
and A(α,β,γ) be the point. Any point on the line (i) is
P(ℓr+x1,mr+y1,nr+z1). .........(ii)
If it is the foot of the perpendicular, from A on the line, then AP is ⊥ to the line, so ℓ(ℓr+x1−α)+m(mr+y1−β)+n(nr+z1−γ)=0
i.e. r=(α−x1)ℓ+(β−y1)m+(γ−z1)n
since ℓ2+m2+n2=1
Putting this value of r in (ii), we get the foot of perpendicular from point A to the line.
Length : Since foot of perpendicular P is known, length of perpendicular,
AP=√[(ℓr+x1−α)2+(mr+y1−β)2+(nr+z1−γ)2]
Equation of perpendicular is given by
x−αℓr+x1−α=y−βmr+y1−β=z−γnr+z1−γ
13. EQUATIONS OF A PLANE :
The equation of every plane is of the first degree i.e. of the form ax+by+cz+d=0, in which a,b,c are constants, where a2+b2+c2z 0 (i.e. a,b,c≠0 simultaneously).
(a) Vector form of equation of plane:
If →a be the position vector of a point on the plane and →n be a vector normal to the plane then it's vectorial equation is given by (→r−→a)⋅→n=0⇒→r⋅→n=d where d=→a⋅→n=constant
(b) Plane Parallel to the Coordinate Planes:
(i) Equation of y -z plane is x=0.
(ii) Equation of z -x plane is y=0.
(iii) Equation of x -y plane is z=0.
(iv) Equation of the plane parallel to x -y plane at a distance c is z=c. Similarly, planes parallel to y -z plane and z -x plane are respectively x=c and y=c.
(c) Equations of Planes Parallel to the Axes:
If a=0, the plane is parallel to x -axis i.e. equation of the plane parallel to x -axis is by+cz+d=0.
Similarly, equations of planes parallel to y -axis and parallel to z -axis are ax+cz+d=0 and ax+by+d=0 respectively.
(d) Equation of a Plane in Intercept Form:
Equation of the plane which cuts off intercepts a,b,c from the axes is xa+yb+zc=1.
(e) Equation of a Plane in Normal Form:
If the length of the perpendicular distance of the plane from the origin is p and direction cosines of this perpendicular are (l m,n ), then the equation of the plane is lx+my+nz=p
(f) Vectorial form of Normal equation of plane :
If ˆn is a unit vector normal to the plane from the origin to the plane and d be the perpendicular distance of plane from origin then its vector equation is →r⋅ˆn=d.
(g) Equation of a Plane through three points:
The equation of the plane through three non-collinear points
(x1,y1,z1),(x2,y2,z2)(x3,y3,z3) is |xyz1x1y1z11x2y2z21x3y3z31|=0
14. ANGLE BETWEEN TWO PLANES:
Consider two planes ax+by+cz+d=0 and a′x+b′y+c′z+d′=0
Angle between these planes is the angle between their normals.
cosθ=aa′+bb′+cc′√a2+b2+c2√a′2+b′2+c′2
∴ Planes are perpendicular if aa′+bb′+cc′=0 and they are parallel if a/a' = b/b' = c/c'.
Planes parallel to a given Plane:
Equation of a plane parallel to the plane ax+by+cz+d=0 is ax+by+cz+d′=0. d' is to be found by other given condition.
15. ANGLE BETWEEN A LINE AND A PLANE :
Let equations of the line and plane be x−x1ℓ=y−y1m=z−z1n and ax+by+cz+d=0 respectively and θ be the angle which line makes with the plane. Then (π/2−θ) is the angle between the line and the normal to the plane.
So sinθ=aℓ+bm+cn√(a2+b2+c2)√(ℓ2+m2+n2)
Line is parallel to plane if θ=0
i.e. if al+bm+cn=0
Line is ⊥ to the plane if line is parallel to the normal of the plane
i.e. if aℓ=bm=cn.
16. CONDITION IN ORDER THAT THE LINE MAY LIE ON THE GIVEN PLANE :
The line x−x1ℓ=y−y1m=z−z1n will ie on the plane Ax+By+Cz+D=0 if (a) Aℓ+Bm+Cn=0 and (b)Ax1+By1+Cz1+D=0
17. POSITION OF TWO POINTS W.R.T. A PLANE :
Two points P(x1,y1,z1)&Q(x2,y2,z2) are on the same or opposite sides of a plane ax+by+cz+d=0 according to ax1+by1+cz1+d & ax2+by2+cz2+d are of same or opposite signs.
18. IMAGE OF A POINT IN THE PLANE :
Let the image of a point P(x1,y1,z1) in a plane ax+by+cz+d=0 is Q(x2,y2,z2) and foot of perpendicular of point P on plane is R(x3,y3,z3), then
(a) x3−x1a=y3−y1b=z3−z1c=−(ax1+by1+cz1+da2+b2+c2)
(b) x2−x1a=y2−y1b=z2−z1c=−2(ax1+by1+cz1+da2+b2+c2)
19. CONDITION FOR COPLANARITY OF TWO LINES :
Let the two lines be
x−α1ℓ1=y−β1m1=z−γ1n1 .......(i)
and x−α2ℓ2=y−β2m2=z−γ2n2........(ii)
These lines will coplanar if |α2−α1β2−β1γ2−γ1ℓ1m1n1ℓ2m2n2|=0
the plane containing the two lines is |x−α1y−β1z−γ1ℓ1m1n1ℓ2m2n2|=0
20. PERPENDICULAR DISTANCE OF A POINT FROM THE PLANE :
Perpendicular distance p, of the point A(x1,y1,z1) from the plane ax+by+cz+d=0 is given by
p=|ax1+by1+cz1+d|√(a2+b2+c2)
Distance between two parallel planes ax+by+cz+d1=0 & ax+by+cz+d2=0 is
|d1−d2√a2+b2+c2|
21. A PLANE THROUGH THE LINE OF INTERSECTION OF TWO GIVENPLANES:
Consider two planes
u≡ax+by+cz+d=0 and v≡a′x+b′y+c′z+d′=0
The equation u+λv=0,λ a real parameter, represents the plane passing through the line of intersection of given planes and if planes are parallel, this represents a plane parallel to them.
22. BISECTORS OF ANGLES BETWEEN TWO PLANES :
Let the equations of the two planes be ax+by+cz+d=0 and a1x+b1y+c1z+d1=0
Then equations of bisectors of angles between them are given by
ax+by+cz+d√(a2+b2+c2)=±a1x+b1y+c1z+d1√(a21+b21+c21)
(a) Equation of bisector of the angle containing origin : First make both constant terms positive. Then +ve sign give the bisector of the angle which contains the origin.
(b) Bisector of acute/obtuse angle : First making both constant terms positive,
aa1+bb1+cc1>0⇒ origin lies in obtuse angle
aa1+bb1+cc1<0⇒ origin lies in acute angle
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