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3d Coordinate Geometry - Notes, Concept and All Important Formula

3D-COORDINATE GEOMETRY

1. DISTANCE FORMULA:

The distance between two points A(x1,y1,z1) and B(x2,y2,z2) is given by AB=[(x2x1)2+(y2y1)2+(z2z1)2]




2. SECTION FORMULAE :

Let P(x1,y1,z1) and Q(x2,y2,z2) be two points and let R(x,y,z) dividePQ in the ratio m1:m2. Then R is

(x,y,z)=(m1x2+m2x1m1+m2,m1y2+m2y1m1+m2,m1z2+m2z1m1+m2)

If (m1/m2) is positive, R divides PQ internally and if (m1/m2) is negative, then externally.

Mid point of PQ is given by (x1+x22,y1+y22,z1+z22)




3. CENTROID OF A TRIANGLE :

Let A(x1,y1,z1),B(x2,y2,z2),C(x3,y3,z3) be the vertices of a triangle ABC. Then its centroid G is given by

G=(x1+x2+x33,y1+y2+y33,z1+z2+z33)




4. DIRECTION COSINES OF LINE :

DIRECTION COSINES OF LINE :

If α,β,γ be the angles made by a line with x -axis, y -axis & z -axis respectively then cosα,cosβ & cosγ are called direction cosines of a line, denoted by 1,m & n respectively and the relation between ,m,n is given by 2+m2+n2=1

Direction cosine of x -axis, y -axis &z -axis are respectively (1,0,0;0,1,0;0,0,1)




5. DIRECTION RATIOS :

Any three numbers a, b, c proportional to direction cosines ,m,n are called direction ratios of the line.

i.e. a=mb=nc

It is easy to see that there can be infinitely many sets of direction ratios for a given line.




6. RELATION BETWEEN D.C'S & D.R'S:

a=mb=nc

2a2=m2b2=n2c2=2+m2+n2a2+b2+c2

=±aa2+b2+c2;m=±ba2+b2+c2;n=±ca2+b2+c2




7. DIRECTION COSINE OF AXES :

Direction ratios and Direction cosines of the line joining two points:

Let A(x1,y1,z1) and B(x2,y2,z2) be two points, then d.r.'s of AB are x2x1,y2y1,z2z1 and the d.c.'s of AB are 1r(x2x1),1r(y2y1) 1r(z2z1) where r=[Σ(x2x1)2]=|AB|




8. PROJECTION OF A LINE ON ANOTHER LINE :

Let PQ be a line segment with P(x1,y1,z1) and Q(x2,y2,z2) and let L be a straight line whose d.c.'s are ,m,n. Then the length of projection of PQ on the lineL is |(x2x1)+m(y2y1)+n(z2z1)|




9. ANGLE BETWEEN TWO LINES :

Let θ be the angle between the lines with d.c.'s l1,m1,n1 and l2,m2, n2 then cosθ=l1l2+m1m2+n1n2. If a1,b1,c1 and a2,b2,c2 be D.R.'s of two lines then angle θ between them is given by

cosθ=(a1a2+b1b2+c1c2)(a21+b21+c21)(a22+b22+c22)




10. PERPENDICULARITY AND PARALLELISM:

Let the two lines have their d.c.'s given by l1,m1,n1 and l2,m2,n2 respectively then they are perpendicular if θ=90 i.e. cosθ=0, i.e. l1l2+m1m2+n1n2=0

Also the two lines are parallel if θ=0 i.e. sinθ=0, i.e. 12=m1m2=n1n2

Note:

If instead of d.c.'s, d.r.'s a1,b1,c1 and a2,b2,c2 are given, then the lines are perpendicular if a1a2+b1b2+c1c2=0 and parallel if a1/a2=b1/b2=c1/c2




11. EQUATION OF A STRAIGHT LINE IN SYMMETRICAL FORM :

(a) One point form : Let A(x1,y1,z1) be a given point on the straight line and l,m,n the d.c's of the line, then its equation is

xx1=yy1m=zz1n=r (say) 

It should be noted that P(x1+lr,y1+mr,z1+nr) is a general point on this line at a distance r from the point A(x1,y1,z1) i.e. AP=r. One should note that for AP=r;1,m,n must be d.c.'s not d.r.'s. If a,b,c are direction ratios of the line, then equation of the line is xx1a=yy1b=zz1c=r but here APr.

(b) Equation of the line through two points A(x1,y1,z1) and B(x2,y2,z2) is xx1x2x1=yy1y2y1=zz1z2z1




12. FOOT, LENGTH AND EQUATION OF PERPENDICULAR FROM A POINT TO A LINE:

Let equation of the line be

xx1=yy1m=zz1n=r.   (say)   ......(i) 

and A(α,β,γ) be the point. Any point on the line (i) is

P(r+x1,mr+y1,nr+z1). .........(ii) 

If it is the foot of the perpendicular, from A on the line, then AP is to the line, so (r+x1α)+m(mr+y1β)+n(nr+z1γ)=0

i.e. r=(αx1)+(βy1)m+(γz1)n

since 2+m2+n2=1

Putting this value of r in (ii), we get the foot of perpendicular from point A to the line.

Length : Since foot of perpendicular P is known, length of perpendicular,

AP=[(r+x1α)2+(mr+y1β)2+(nr+z1γ)2]

Equation of perpendicular is given by

xαr+x1α=yβmr+y1β=zγnr+z1γ




13. EQUATIONS OF A PLANE :

The equation of every plane is of the first degree i.e. of the form ax+by+cz+d=0, in which a,b,c are constants, where a2+b2+c2z 0 (i.e. a,b,c0 simultaneously).

(a) Vector form of equation of plane:

If a be the position vector of a point on the plane and n be a vector normal to the plane then it's vectorial equation is given by (ra)n=0rn=d where d=an=constant

(b) Plane Parallel to the Coordinate Planes:

(i) Equation of y -z plane is x=0.

(ii) Equation of z -x plane is y=0.

(iii) Equation of x -y plane is z=0.

(iv) Equation of the plane parallel to x -y plane at a distance c is z=c. Similarly, planes parallel to y -z plane and z -x plane are respectively x=c and y=c.

(c) Equations of Planes Parallel to the Axes:

If a=0, the plane is parallel to x -axis i.e. equation of the plane parallel to x -axis is by+cz+d=0.

Similarly, equations of planes parallel to y -axis and parallel to z -axis are ax+cz+d=0 and ax+by+d=0 respectively.

(d) Equation of a Plane in Intercept Form:

Equation of the plane which cuts off intercepts a,b,c from the axes is xa+yb+zc=1.

(e) Equation of a Plane in Normal Form:

If the length of the perpendicular distance of the plane from the origin is p and direction cosines of this perpendicular are (l m,n ), then the equation of the plane is lx+my+nz=p

(f) Vectorial form of Normal equation of plane :

If ˆn is a unit vector normal to the plane from the origin to the plane and d be the perpendicular distance of plane from origin then its vector equation is rˆn=d.

(g) Equation of a Plane through three points:

The equation of the plane through three non-collinear points

(x1,y1,z1),(x2,y2,z2)(x3,y3,z3) is |xyz1x1y1z11x2y2z21x3y3z31|=0




14. ANGLE BETWEEN TWO PLANES:

Consider two planes ax+by+cz+d=0 and ax+by+cz+d=0

Angle between these planes is the angle between their normals.

cosθ=aa+bb+cca2+b2+c2a2+b2+c2

Planes are perpendicular if aa+bb+cc=0 and they are parallel if a/a' = b/b' = c/c'.

Planes parallel to a given Plane:

Equation of a plane parallel to the plane ax+by+cz+d=0 is ax+by+cz+d=0. d' is to be found by other given condition.




15. ANGLE BETWEEN A LINE AND A PLANE :

Let equations of the line and plane be xx1=yy1m=zz1n and ax+by+cz+d=0 respectively and θ be the angle which line makes with the plane. Then (π/2θ) is the angle between the line and the normal to the plane.

So sinθ=a+bm+cn(a2+b2+c2)(2+m2+n2)

Line is parallel to plane

Line is parallel to plane if θ=0

i.e. if al+bm+cn=0

Line is to the plane if line is parallel to the normal of the plane

i.e. if a=bm=cn.




16. CONDITION IN ORDER THAT THE LINE MAY LIE ON THE GIVEN PLANE :

The line xx1=yy1m=zz1n will ie on the plane Ax+By+Cz+D=0 if (a) A+Bm+Cn=0 and (b)Ax1+By1+Cz1+D=0




17. POSITION OF TWO POINTS W.R.T. A PLANE :

Two points P(x1,y1,z1)&Q(x2,y2,z2) are on the same or opposite sides of a plane ax+by+cz+d=0 according to ax1+by1+cz1+d  & ax2+by2+cz2+d are of same or opposite signs.




18. IMAGE OF A POINT IN THE PLANE :

IMAGE OF A POINT IN THE PLANE :

Let the image of a point P(x1,y1,z1) in a plane ax+by+cz+d=0 is Q(x2,y2,z2) and foot of perpendicular of point P on plane is R(x3,y3,z3), then

(a) x3x1a=y3y1b=z3z1c=(ax1+by1+cz1+da2+b2+c2)

(b) x2x1a=y2y1b=z2z1c=2(ax1+by1+cz1+da2+b2+c2)




19. CONDITION FOR COPLANARITY OF TWO LINES :

Let the two lines be

xα11=yβ1m1=zγ1n1 .......(i) 

and xα22=yβ2m2=zγ2n2........(ii) 

These lines will coplanar if |α2α1β2β1γ2γ11m1n12m2n2|=0

the plane containing the two lines is |xα1yβ1zγ11m1n12m2n2|=0




20. PERPENDICULAR DISTANCE OF A POINT FROM THE PLANE :

Perpendicular distance p, of the point A(x1,y1,z1) from the plane ax+by+cz+d=0 is given by

p=|ax1+by1+cz1+d|(a2+b2+c2)

Distance between two parallel planes ax+by+cz+d1=0 & ax+by+cz+d2=0 is 

|d1d2a2+b2+c2|




21. A PLANE THROUGH THE LINE OF INTERSECTION OF TWO GIVENPLANES:

Consider two planes

uax+by+cz+d=0 and vax+by+cz+d=0

The equation u+λv=0,λ a real parameter, represents the plane passing through the line of intersection of given planes and if planes are parallel, this represents a plane parallel to them.




22. BISECTORS OF ANGLES BETWEEN TWO PLANES :

Let the equations of the two planes be ax+by+cz+d=0 and a1x+b1y+c1z+d1=0

Then equations of bisectors of angles between them are given by

ax+by+cz+d(a2+b2+c2)=±a1x+b1y+c1z+d1(a21+b21+c21)

(a) Equation of bisector of the angle containing origin : First make both constant terms positive. Then +ve sign give the bisector of the angle which contains the origin.

(b) Bisector of acute/obtuse angle : First making both constant terms positive,

aa1+bb1+cc1>0 origin lies in obtuse angle

aa1+bb1+cc1<0 origin lies in acute angle



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