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Area under the curve - Notes, Concept and All Important Formula

AREA UNDER THE CURVE

Area bounded by the curve
1. The area bounded by the curve y=f(x), the x -axis and the ordinates x=a & x=b is given by, 
A=baf(x)dx=baydx,f(x)0



2. If the area is below the x -axis then A is negative. The convention is to consider the magnitude only i.e.
A=|baydx| in this case.



area bounded by curve taking small division of y axis.
3. The area bounded by the curve x=f(y), y -axis & abscissa y=c, y=d is given by, Area =dcxdy=dcf(y)dy,f(y)0



Area between two curve
4. Area between the curves y=f(x) & y=g(x) between the ordinates x=a & x=b is given by,
A=baf(x)dxbag(x)dx
=ba[f(x)g(x)]dx,f(x)g(x)x(a,b)



5. Average value of a function y=f(x) w.r.t. x over an interval ax b is defined as: y(av)=1babaf(x)dx.



6. CURVE TRACING :

The following outline procedure is to be applied in Sketching the graph of a function y=f(x) which in turn will be extremely useful to quickly and correctly evaluate the area under the curves.

(a) Symmetry : The symmetry of the curve is judged as follows:

(i) If all the powers of y in the equation are even then the curve is symmetrical about the axis of x.

(ii) If all the powers of x are even, the curve is symmetrical about the axis of y.

(iii) If powers of x & y both are even, the curve is symmetrical about the axis of x as well as y.

(iv) If the equation of the curve remains unchanged on interchanging x and y, then the curve is symmetrical about y=x

(v) If on replacing 'x' by '-x' and 'y' by '- y ', the equation of the curve is unaltered then there is symmetry in opposite quadrants, i.e. symmetric about the origin.


(b) Find dydx  & equate it to zero to find the points on the curve where you have horizontal tangents.

(c) Find the points where the curve crosses the x -axis & also the y -axis.

(d) Examine if possible the intervals when f(x) is increasing or decreasing. Examine what happens to 'y' when x or .




7. USEFUL RESULTS :

(a) Whole area of the ellipse, x2a2+y2b2=1 is πab.

(b) Area enclosed between the parabolas y2=4ax & x2=4by is 16ab/3

(c) Area included between the parabola y2=4ax & the line y=mx is 8a2/3m3

(d) Area enclosed by the parabola and its double ordinate P,Q is two-third of area of rectangle PQRS, where R,S lie on tangent at the vertex.



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